Question

1 by under root 4 subtract under root 3 rationalise the denominator

Answer 1

Answer:

$= \frac{1}{ \sqrt{4} - \sqrt{3} } \\ \\ = \frac{1( \sqrt{4} + \sqrt{3}) }{( \sqrt{4} - \sqrt{3} )( \sqrt{4} + \sqrt{3} ) } \\ \\ = \frac{ \sqrt{4} + \sqrt{3} }{( \sqrt{4} ) {}^{2} - ( \sqrt{3}) {}^{2} } \\ \\ = \frac{ \sqrt{4} + \sqrt{3} }{4 - 3} \\ \\ = \frac{ \sqrt{4} + \sqrt{3} }{1} \\ \\ = \sqrt{4} + \sqrt{3}$

Step-by-step explanation:

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