Math, asked by maquib71, 15 days ago

1(c+2) +3(c+5)+1=0, find the value of c​

Answers

Answered by ANSHURAJ2123
0

Answer:

1c+2+3c+15+1 = 0

4c+18 = 0

4c = -18

c = -18/4

Step-by-step explanation:

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Answered by AzorAhai
0

Answer:

c = -9/2

Step-by-step explanation:

1(c+2) +3(c+5) +1 =0

=>c+2+3c+15+1=0

=>4c=-18

=>c= -9/2

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