Question

1 c.c. n2o at NTP contains

Answer 1

(1.32/224) x 10 rise to power 23 Electrons.  

Else (6.02/22400) x 10 raise to power 23 Molecules.  

Else (108/224) x 10 raise to power 22 Atoms

Hence given input from the question , you have to derive formula as per the question.

Then student will get answer easily and get prepared without meeting any trouble of it.  

Answer 2

At N.T.P 22400 cc of N₂O =6.02 x 10²³ molecules
1 cc contains = (6.02 x 10²³) / 22400 molecules

N₂O contains 3 atoms, so
= (3 x 6.02 x 10²³) / 22400 atoms
=1.8 / 224 x 10²² atoms