Question

1 c.c. N₂O at NTP contains :
(a) 1.8/224 × 10²² atoms
(b) 6.02/22400 × 10²³ molecules
(c) 1.32/224 × 10²³ electrons (d) All of these

Answer 1

1 c.c. N₂O at NTP contains 1.8/224 × 10²² atoms (or)  6.02/22400 × 10²³ molecules (or) 1.32/224 × 10²³ electrons

Explanation:

NTP conditions are nothing but Normal Temperature and Pressure conditions

According to Avogadro's law every one mole of substance are 22400 cc substance contains $6.023 \times 10^{23}$ molecules

Then 1 c.c. $N_2O$ containing molecules = $\frac{6.023\times 10^{23}}{22400}$

$N_2O$ Molecule is a molecule that contains three atoms.

Hence, 1 c.c $N_2O$ containing atoms = $\frac{6.023\times 10^{23}\times3}{22400}=\frac{1.8\times10^{22}}{224}$ atoms

And, No. of electrons in $N_2O$ =$7\times2 +8=22$

Therefore, 1 c.c $N_2O$ containing electrons = $\frac{6.023\times 10^{23}\times22}{22400}=\frac{1.32\times10^{23}}{224}$ electrons

Hence, the correct answer is option (d)