Chemistry, asked by 01aaradhya, 1 year ago

1) Calculate mass of 1 molecule of O2...

2) How many molecules are in 17g of NH3??

Answers

Answered by Anonymous
9
1) Molar mass of O2 = 32

Now, 1 mole means 6.022×10²³ molecules.

Conversely,

6.022×10²³ molecules in 1 mole.

1 molecule in  \frac{1}{6.022 \times {10}^{23} } \: moles

Now, n = Mass/Molar mass

Or, \frac{1}{6.022 \times {10}^{23}} \: moles = \frac{mass}{32}

Or, Mass =  \frac{32}{6.022 \times {10}^{23} }

Or, Mass = 5.314 \times {10}^{ - 23}

2) Molar mass of NH3 = 14+3 = 17

Now, Given mass = 17

Let Number of moles be "n".

Then,

n = Given mass ÷ Molar mass

Or, n = 17/17 = 1.

So, 1 mole means 6.022×10²³ molecules.

Hence, there are 6.022×10²³ molecules in 17g of NH3.

01aaradhya: arey but this formula is used for finding no. of moles
Anonymous: Which formuka
Anonymous: Which question?
01aaradhya: no. of molecules = no. of moles * 6.022*10^23
01aaradhya: so in 2nd question, 1*6.022*10^23
01aaradhya: =6.022*10^23
01aaradhya: molecules
Anonymous: Where have i done that
Anonymous: n i hold number of molecuele see carefully
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