Question

1. Calculate number of moles of 1 point
NH3 formed by reaction of 2
moles of N2 and 2 moles of H2.
N2 (g) + 3H2(g) 2NH3(g)
options are as follows
4 mol
2 mol
1.33 mol
0.75 mol​

Answer 1

Explanation:

ANSWER

Volume = 1 L

Temperature = 400 K

Equilibrium constant,  Kc=274

The Net balanced chemical reaction is,

                                          N2+3H2→2NH3

Initial concentration           1         2             0

At equilibrium                  (1-x)      (3-3x)      2x

The expression for equilibrium constant is,

Kc=[N2][H2]3[NH3]2

By rearranging the terms, we get the value of x.

x=0.381 mole/L

The concentration of NH3 at equilibrium = 2x  =2×0.381=0.762mole/L