Question

1. Calculate number of neutrons present in 12 x103 atoms of oxygen (200): (Given: N=6 x 1023) (a) 1800 (b) 1600 (c) 1800 NA a 3200 NA​

Answer 1

C) 1800NA

Explanation:

Given: NA = 6 × 10²³

Atomic number = 8

Atomic mass = 17

Number of neutrons in single atom = 17 - 8

                                  = 9

Total number of neutrons = 9 × 12 × 10³  

                                             = 9 × 12 × NA/ 6 × 10²³

                                             = 1800 NA