1. Calculate the amount and the compound interest on Rs
60000 in 2 years when the rate of interest for successive
years is 8% and 10% respectively
Answers
Calculate the amount and the compound interest on Rs
. 60000 in 2 years when the rate of interest for successive years is 8% and 10% respectively.
Let 'r₁' be the rate of interest for the first year.
Let 'r₂' be the rate of interest for the second year.
Amount = Principal (1 + \frac{r₁}{100})(1 + \frac{r₂}{100})
= 60000
= 60000
= Rs. 68688
- Hence, the Amount is Rs. 68688
______________________________
Compound Interest = Amount - Principal
= 68688 - 60000
= Rs. 8688
- Hence, the Compound Interest is Rs. 8688
Hope this helps! ♡
Answer:
\dag\:\:\underline{\sf Question:- }†
Question:−
Calculate the amount and the compound interest on Rs
. 60000 in 2 years when the rate of interest for successive years is 8% and 10% respectively.
\dag\:\:\underline{\sf Answer:- }†
Answer:−
\begin{gathered}Given:- \left[\begin{array}{ccc}Principal = Rs. 60000\\Time =2 years\\Rate \: of \: interest (in \: percent) \: = 8 \: and \: 10 \: respectively\end{array}\right]\end{gathered}
Given:−
⎣
⎢
⎡
Principal=Rs.60000
Time=2years
Rateofinterest(inpercent)=8and10respectively
⎦
⎥
⎤
To \: find:- \left \{ {{Amount} \atop {Compound \: Interest}} \right.Tofind:−{
CompoundInterest
Amount
Let 'r₁' be the rate of interest for the first year.
Let 'r₂' be the rate of interest for the second year.
Amount = Principal (1 + \frac{r₁}{100})(1 + \frac{r₂}{100})
= 60000 (1 + \frac{6}{100})(1 + \frac{8}{100})(1+
100
6
)(1+
100
8
)
= 60000 (1.06)(\frac{27}{25})(1.06)(
25
27
)
= Rs. 68688
Hence, the Amount is Rs. 68688
______________________________
Compound Interest = Amount - Principal
= 68688 - 60000
= Rs. 8688
Hence, the Compound Interest is Rs. 8688
Hope this helps! ♡