Question

1. Calculate the amount of heat required to
convert 80 g of ice at 0 °C into water at the
same temperature. (Specific latent heat of
fusion of ice = 80 cal/g) ​

Answer 1

Answer:

mass of ice=80g

heat required to convert water at 0°c is=

H=m× spesific latent heat of fusion of ice

=80×80=6400cal