Question

1 Calculate the compound interest on Rs. 10,000 for two years at 8 % p.a. *

Answer 1

Solution:

Given,

Principal(p) = Rs.10,000

Time(n) = 2years

Rate = 8% p.a

We know formula,

${ \green{ \bigstar { \red{\boxed{\sf \: P\bigg (1+\dfrac{R}{100} \bigg)^{ {}^{n} }}}}}}$

A/Q,

$\implies{\sf \: P\bigg (1+\dfrac{R}{100} \bigg)^{ {}^{n} }}$

${ \implies{\sf \: 10000 \bigg (1+\dfrac{R}{100} \bigg)^{ {}^{n}} }}$

${ \implies{\sf \: 10000 \bigg(1+\dfrac{8}{100} \bigg)^{ {}^{2} }}}$

${ \implies{\sf \: 10000 \bigg(\dfrac{100 + 8}{100} \bigg)^{ {}^{2} }}}$

${ \implies{\sf \: 10000 \bigg(\dfrac{108}{100} \bigg)^{ {}^{2} }}}$

${ \implies{\sf \: 10000 \times \dfrac{108}{100} \times \dfrac{108}{100} }}$

${ \implies{\sf \: 1 \cancel{0000} \times \dfrac{108}{ 100} \times \dfrac{108}{100} }}$

..

${ \implies{\sf \dfrac{108}{ 100} \times \dfrac{108}{100} }}$

$\red \bigstar {\sf { \boxed{ \sf = { \pmb{ \pmb {Rs.1164}}}}}}$

Now we've to calculate compound interest

As we know the formula,

${ \green{ \bigstar { \blue{\boxed{\sf \: Compound \: Interest=Amount-Principal}}}}}$

So,

${ \implies\sf \: Compound \: Interest=Amount-Principal}$

${ \implies\sf \: C.I. = ₹ 11664 - ₹ 10000}$

${ \implies\sf \: C.I. = ₹ 1664}$

$\red \bigstar {\sf { \boxed{ \sf = { \pmb{ \pmb {Compound \: Interest = Rs.1164}}}}}} \red\bigstar$

Additional Information

${\red{\bigstar{ \boxed{ \sf{ Simple \: Interest = \dfrac{Principal\times Rate\:Of\:Interest\times Time}{100}}}}}}$

${\green{\bigstar{ \boxed{ \sf{ Principal = \dfrac{Simple\:Interest\times 100}{Rate\:Of\:Interest\times Time}}}}}}$

${\blue{\bigstar{ \boxed{ \sf \: Time = \dfrac{Simple\:Interest\times 100}{Rate\:Of\:Interest\times Principal }}}}}$

${\pink{\bigstar{ \boxed{ \sf \: Rate \: Of \: Interest = \dfrac{Simple\:Interest\times 100}{Time\times Principal }}}}}$

@itzadi61