1 Calculate the distance between the parallel lines 4x+3y+12=0 and 4x+3y-6=0 from origin
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Answered by
1
Answer:
the distance between
Step-by-step explanation:
4x+3y+12=0 and 4x+3y-6=0
4x-4x
==0x
3y-3y
==0
12-6
,=6
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Answered by
0
Answer:
for general pair of parallel lines =
ax +by +c=0
ax+ by + d=0
distance between them=
|c-d|/sqrt(a^2+b^2)
=|-6-12|/(sqrt(4^2+3^2))
=18/sqrt(25)
=18/5
=3.6
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