Question

1. Calculate the ethalpy change for the reaction,C (graphite)+1/2O2--->CO(g) from
following thermochemical equations.
AH = -393.5 kJ
C (graphite) + O2(g) --> CO2(g)
--- (1)
CO(g) +1/2 02 (g) ---> CO2(g)
AH° = -283.0 kJ ---> (2)
​

Answer 1

Answer:

The first reaction is exothermic and the second one is endothermic. If a mixture of steam and O

2

is passed over coke and temperature is kept constant, the conversion of each to CO should not show any heat change,

i.e.,totalheatevolvedinI=totalheatabsorbedinII.

n

1

×2×110=n

2

×132

∴

n

2

n

1

=

110×2

132

=

1

0.6