Question

1.) Calculate the force acting on a car of mass 1000kg to change its
velocity from 20m/s to 40m/s in 10s.
​

Answer 1

Explanation:

given,

m=1000kg,u=20m/s,v=40m/s,t=10s

acceleration (a) = 20m/s

force(f) = ma = (1000×20) N = 20000N

Answer 2

QUESTION :-

Calculate the Force acting on a Car of Mass 1000kg to change its

Velocity from 20 m/s to 40 m/s in 10 Seconds -

GIVEN:-

Initial Velocity (u) of the Car = 20 m/s

​Final Velocity (v) of the Car = 40 m/s

Time Taken (t) = 10 Seconds

Mass (m) = 1000 kg

TO FIND:-

The Force acting on the Car

SOLUTION :-

Using the Second Law of Motion's Formula, (i.e.), $\bold{F = \frac{m (v - u)}{t}}$, we get -

$\bold F = \frac{1000\:kg\:(40 - 20\:m/s)}{10s} = \frac{20,000}{10} =\bold{2,000\:kgms^{-1}}$

∴ The Force Acting on the Car of Mass 1000 kg is = 2,000 kgm/s