Question

1. Calculate the magnitude and direction of the electric
field which keeps a proton just floating. Given the
mass of proton 1.67 x 10-27 kg, charge on proton
1.6 x 10-19 C and g = 9.8 ms-2.​

Answer 1

Answer:

Electric field E = F / q

In order to keep one proton float, the downward force mg exerted by proton must be balanced by electric field.

Force exerted by proton = mg = 16.366 × 10^-27kg

q = 1.6 * 10^-19 C

Electric field E = (16.366 × 10^-27)/ (1.6 × 10^-19)

= 10.22875 × 10^-8 N/C

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