Question

1 . calculate the mass of sodium acetate (CH3COONa) required to make 500ml of 0.0375 molar aqueous solution. Molar mass of sodium acetate is 82.0245g mol-1​

Answer 1

Answer:

ans=1.5375

Explanation:

as M=n/V(L)

and n=given mass / molar mass

so 0.0375=2x/82

x=1.5375

Answer 2

Explanation:

0.375 M solution of CH3

COONa = 0.375 moles of CH3

COONa/1000ml

No. of moles of CH 3

COONa in 500ml = 1000

0.375×500=0.1875 moles

Molar mass of sodium acetate = 82.0245 g/mole

∴ mass of CH3

COONa required =82.0245×0.1875=15.38g