Question

1. Calculate the mass of the following: (a) 0.2 mole of sucrose (C12H22O11) (b) 2 moles of CO2 (c) 2 moles of CaCO3 (d) 10 moles of H2O​

Answer 1

Answer:

a) 68.4g

b) 88g

c) 200g

d) 180g

Explanation:

Formula used here

No. of Moles = Given Mass/Molar mass

a) 0.2 moles= given mass/ 12×12+1*22+16*11

0.2 moles=. given mass/144+22+176

0.2 moles=. given mass/ 342

0.2×342=. given mass

68.4g

b) given mass=. 2(12+16*2)

given mass=. 2(44)

given mass=. 88g

88g

c). given mass=. 2(40+12+16*3)

given mass=. 2(100)

given mass=. 200g

200g

d). given mass=. 10(1*2+16)

given mass=. 10(18)

given mass=. 180g

180g