Question

1))Calculate the momentum of a toy car of mass 200 g moving with a speed of 5m/s.

(2)What is the change in momentum of a car weighting 1500 kg when it's speed increases from 36 km/h to 72 km/h uniformly?

#☺5pts

Please help....

Answer 1

Hi Friend,

Here is the answer
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1) p=mv
mass= 200g= 200/1000= 0.2 kg

p= 0.2×5
= 1 kgm/s

2) mass= 1500kg
initial velocity = 36km/h= 36×5/18= 10m/s
Final velocity = 72 km/h= 72×5/18= 20m/s

therefore,

Initial momentum= 1500×10=15000kgm/s
Final momentum= 1500×20= 30000kgm/s

The change momentum
= m(v-u)
= 1500(20-10)
= 1500×10
= 15000kgm/s

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Hope my answer helps you
Mark my answer as brainliest if you like :)

Regards,
Shobana
^_^

Answer 2

$1. Given,\\mass = 200g\ or \ 0.2 \ kg\\velocity = 5 \ m/s \\\\we\ know,\\ momentum = mass \times velocity\\~~~~~~~~~~~~~~~~~ = 0.02 \times 5\\~~~~~~~~~~~~~~~~~ = 1 \ m \ s^{-2}\\\\2. Given, \\mass = 1500 kg\\initial \ velocity(u) = 36km/hr \ or \ 10 m/s\\final \ velocity(v) = 72 km/hr \ or \ 20 m/s\\\\we \ know,\\momentum = mv - mu\\~~~~~~~~~~~~~~~~~=1500 \times20 - 1500\times20\\~~~~~~~~~~~~~~~~~= 1500(20-10)\\~~~~~~~~~~~~~~~~~ = 1500 \times 10\\~~~~~~~~~~~~~~~~~=15000 \ kg \ m/s$