Question

1 Calculate the no. of electrons present in 1.5g of
${so4}^{2 - }$

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Answer 1

Answer:

4.69 x 10^23 electrons

Explanation:

Molecular weight of $SO_4^2-$ = 96g

1 mole of $SO_4^2-$ = 96g

? moles of $SO_4^2-$ = 1.5g

1.5/96 = 0.0156 moles

1 mole of $SO_4^2-$ = 16 + 8x4 + 2  = 50 x $6.023 * 10^{23}$ electrons

0.0156 moles of $SO_4^2-$ = ? electrons

0.0156 x 50 x $6.023 * 10^{23}$ = 0.78 x $6.023 * 10^{23}$electrons

                                          = 4.69 x 10^23 electrons