1. Calculate the number of electrons present in 1.6g of methane.
2. A mixture of formic acid and oxalic acid is treated with conc. h2so4 the gas evolved is passed through potassium hydroxide. The decrease in volume is 1/6. Calculate the molar ratio of two acids.
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Explanation:
Molar mass of methane
(CH4) =12+4×1 = 16g
16 g of methane contain molecule
6.022× 10^23/ 16 g ×1.6 = 6.022× 10^23
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