1. Calculate the number of moles in 52 g of He
2. Calculate the number of moles in 12.044 × 1023 number of He
3. Calculate the molar mass of 0.5 mole of N2 gas
4. Calculate the molar mass 0.5 mole of N atoms
5. Calculate the molar mass of 3.011 × 1023 number of N atoms
6. Calculate the molar mass of 6.022 × 1023 number of N2 molecules
7. Calculate the number of particles in 46 g of Na atoms
8. Calculate the number of particles in 8 g O2 molecules
9. Calculate the number of particles in 0.1 mole of carbon atoms
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Answers
1. The molar mass that is the mass of 6.022 X 1023 atoms of helium is 4g. Hence 1 mole of He = 4 g of He = 6.022 X 1023atoms of He. 1 g of He = (6.022 X 1023) / 4 atoms of He. 52 g of He = (6.022 X 1023X 52 ) / 4 atoms of He.
2. There are 2 moles of He atom in 12.044 X 1023 atoms of He.
3. Molar mass of N2 is 28(since atomic weight of nitrogen is 14and forN2=14*2). So mass of 1 mole of N2 is 28g.Therefore mass of 0.5 mole is 28/2 =14g.
4. The mass of 0.5 mole of nitrogen atom is 7 g.
The number of the moles is equivalent to the given mass which is then divided by the total molar mass.
5. 214=7g of N.
6. The mass of number of molecule is 28 grams.
Number of moles is given by :
Mass of N₂ = No. of moles × Molar mass of N₂
Therefore, we can say that the mass of number of. molecule is 28 grams. Learn more, Mole concept. brainly.in/question/2274002.
7. atomic mass of Na=23u
Number of particles=Number of Moles x N
⇒(given weight/ Gram atomic weight) x 6.023 x 10²³
=(46/23)x 6.023 x 10²³
=2x 6.023 x 10²³
⇒12.046 x 10 ²³Na particles
∴46 g of Na contains 12.044 x 10 ²³
8. 1 moleculer mass of any gas contains 1 mole molecules….. for o2 … o2 has 32 gm moleculer mass …. No.of moles=given mass÷ moleculer mass
No. Of moles of o2= 8÷32= .25 moles
So no. Of molecules= .25 × 6.024×10^24
9. According to Avagadro number
.
1mole of carbon = 12g = 6.022×10^23
so
0.1 moles =0.1×6.022×10^23
6.022×10^22
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Answer:
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Explanation:
1. The molar mass that is the mass of 6.022 X 1023 atoms of helium is 4g.
Hence 1 mole of He = 4 g of He = 6.022 X 1023 atoms of He.
1 g of He = (6.022 X 1023) / 4 atoms of He.
52 g of He = (6.022 X 1023 X 52 ) / 4 atoms of He
2. The molar mass that is the mass of 6.022 X 1023 atoms of helium is 4g. Hence 1 mole of He = 4 g of He = 6.022 X 1023 atoms of He.
1 g of He = (6.022 X 1023) / 4 atoms of He.
52 g of He = (6.022 X 1023 X 52 ) / 4 atoms of He
3. 1 mole of N2 = Gram molecular mass of N2
Or 1 mole of N2 = 28 gm.
∴ 0.5 mole of N2 gas = 0.5 × 28.
= 14 gm of N2
4. The mass of 0.5 mole of nitrogen atom is 7 g.
The number of the moles is equivalent to the given mass which is then divided by the total molar mass.
5. we know that ....
1 mole of atoms = 6.022× 10 ^23 atoms
so,
6.022 x 10^23 atoms = 1 mole
1 atoms = 1/6.022×10^23 mole
3.011 x 10^23 atoms =
=3.011 ×10^23/6.022×10^23
=1/2 mole
and we also know that ....
1 mole of atom = atomic weight
so,
1 mole of nitrogen.= 14 grams
1/2 mole of nitrogen = 1/2 x 14 =7 grams
so..mass of nitrogen atom = 7 grams
6. Number of moles is given by :
Mass of N₂ = No. of moles × Molar mass of N₂
Therefore, we can say that the mass of number of. molecule is 28 grams.
7. atomic mass of Na=23u
Number of particles=Number of Moles x N
⇒(given weight/ Gram atomic weight) x 6.023 x 10²³
=(46/23)x 6.023 x 10²³
=2x 6.023 x 10²³
⇒12.046 x 10 ²³Na particles
∴46 g of Na contains 12.044 x 10 ²³
8. No of molecules=no of moles ' Avagadro ' no. = 1/4 × 6.022 × 10^23. =1.5055 × 10^23.
9.
according to Avagadro number
1mole of carbon = 12g = 6.022×10^23
so
0.1 moles =0.1×6.022×10^23
6.022×10^22