1. Calculate the number of moles of solute in the following
volumes of solution.
(a) 50 cm3 of 0.5 moldm-3 solution. (b) 100 cm3 of 0.5 moldm-3 of
solution.
(c) 250 cm3 of 2 mol/ dm3 of solution (d) 2 dm3 of 2 moldm-3 of
solution.
2. Find the masses of solute in the following volumes.
(a) 24 cm3 of 0.1 moldm-3 NaCl. (b) 50 cm3 of 1 Molar (M)
Sulfuric acid.
(c) 100 cm3 of 4g/dm3 NaOH (d) 250 cm3 of 11.1gdm-3 CaCO3.
3. Express the following concentrations in moldm-3
(a) 20g NaOH in 500 cm.3 (b) 0.5 g HCl in 25 cm.3 (c) 5.85g
NaCl in 40 cm3 (d) 1.06g Na2CO3 in 20 cm3.
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Answer:
What is the formula for molar concentration?
M = \frac{n}{v}
M = molar concentration
n = moles of solute
v = liters of solution
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