Question

1. Calculate the number of water molecule
present in one drop of water which weighs 0.18g?​

Answer 1

The molar mass of water (H2O) is 18g/mol (M (O) =16. M (H )=1). So the number of moles in this drop of water is 0.01mol. To find the number of molecules in this drop of water you multiply the number of moles that is 0.01 by the Avogadro constant is known as NA=6.02*10^23.

Answer 2

Hi mate

Question:

Calculate the number of water molecules present in one drop of water which weights 0.18g.

Solution

Mass of water = 0.18g

$No \: Of \: Mole = Mass \div Molar \: Mass$

= 0.18/18

= 0.01 Mole

$No.of.molecules = No.of.Moles × Avagadros Number$

= 0.01 × 6.023 × 10²³

= 0.06023 ×10²³

= 6.023 × 10²¹

Therefore, 6.023 × 10²¹ molecules is your answer.

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