1. Calculate the number of water molecule
present in one drop of water which weighs
0.18 g.
Answers
Answered by
0
Answer:
NA=6.02*10^23
Explanation:
The molar mass of water (H2O) is 18g/mol (M (O) =16. M (H )=1). So the number of moles in this drop of water is 0.01mol. To find the number of molecules in this drop of water you multiply the number of moles that is 0.01 by the Avogadro constant is known as NA=6.02*10^23.
Answered by
3
Answer:
6.023×10²³ is the answer
Explanation:
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