Question

1 Calculate the time period of simple pendulum of length 0.84 m when g = 9.8 ms ?
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Answer 1

Answer:

Time period of simple pendulum = 2π√(l/g)

= 2π√(0.84/9.8) = 2π√0.0857

= 2π(0.29) = 1.822s

Answer 2

Answer:

T=1.83953s

Explanation:

T=2π*$\sqrt\frac{l}{g}$

T=2π*$\sqrt\frac{0.84}{9.8}$

T=2π*0.29277

T=1.83953s

Therefore, time period of the simple pendulum is 1.83953s.