Question

1.Calculate the total displacement from A to D

2.is the motion uniform? why or why not ?

3.Calculate deceleration from B to C.

4.calculate acceleration from A to B and declaration from B to D

5.is the motion uniform?why or why not?

6. Write the time periods during which acceleration is uniform.
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Answer 1

1. Velocity = Displacement/Time

Displacement = Velocity × Time = Area of the graph

> ½ × AD × BE

> ½ × 6 × 25

> 75m.

The motion is non uniform as the velocity isn't constant.

Deceleration between B to C

> ∆V/∆t

> 25 - 17.5 /1

> 7.5 m/s²

Acceleration from A to B

> 25/3 m/s²

> 8.33 m/s²

Deceleration from B to D

> 25/3 m/s²

> 8.33 m/s²

The acceleration is uniform from A to B and from B to D

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Answer 2

Answer:

☆Answered by Rohith kumar. R.

☆We know that

Velocity =Displacement/ time taken

Displacement = velocity =Area of given

time .

graph

=1/2×AD×BE

= 1/2×6×25

=75m.

▪If the velocity is not constant the motion is non uniform motion .

And if we take Deaccleeration of B to C

=DeltaV

deltat

=25-17.5

1

=7.5 m/s^2.

▪Acceleration from A to B if we take 25/3m/s^2=83m/s^2

And next Deaccleeration from B to D if we take

25/3m/s^2=83m/s^2.

The acceleration is same between A to B and B to D

Hope it helps u mate.

Thank you.