Question

1) Calculate the volume of CO2 at STP by decomposing 1 mole of CaCO3 (CaCO3-Ca0+C02]​

Answer 1

. Answer:

11.2 litre

Explanation:

No.of moles of CaCO3 = 50/100= 0.5

According to reaction, 1 mole of CaCO3 gives 1 mole of CO2

So 0.5 moles of CaCO3 will give 0.5 moles of CO2.

Now at STP 1 mole of any gas = 22.4 L

So 0.5 moles of CO2 gas = 22.4×0.5 = 11.2 L

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