Math, asked by ScaelettSera19, 8 months ago

1. Can we say whether the following numbers are perfect squares? How do we know?
(i) 1057
(ii) 23453
(m) 7928
(iv) 222222
(v) 1069
(vi) 2061
If they are perfect squares/not perfect squares please explain how/why.

Please guys answer this as fast as you can...

Answers

Answered by sq2409ak
2

Answer:

(i), (ii) , (iii) , (iv) are not a perfect square

v) and vi) are a perfect square

Step-by-step explanation:

we know that if a no. is a perfect square it should had 0, 1, 4, 6 , 9 at the last digit

and if it is not then it is not a perfect square .

so in the given numbers we have (i ) no. have 7 as the last digit so it is not a perfect square

by this only we will get to know that ( ii) , iii) and iv is also not a perfect square .

and then in (v) no. and in (vi) no.we have 9 and 1 respectively as the last digit s

so by this i prove that

Hence proved !!!!

always welcome

i hope it will help you in future

Answered by rishabh874313
1

Note : We know that the natural number ending with 0, 2, 3, 7 and 8 are not perfect square

  1. 1057 - so, here it is ending with 7 then it is not a perfect square.
  2. 23453 - so, here it is ending with 3 then it is not a perfect square.
  3. 7928 - so, here it is ending with 8 then it is not a perfect square.
  4. 222222 - so, here it is ending with 2 then it is not a perfect square.
  5. 1069 - so, here it is ending with 9 then it is a perfect square.
  6. 2061 - so, here it is ending with 1 then it is a perfect square.
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