Question

1 car starts from rest and moves along the x axis with constant acceleration of 5 metre per second square for 8 seconds if it then continuous with constant velocity why distance will the car cover in 12 seconds since it started from the rest​

Answer 1

u(initial v)= 0 given

a= 5 m/s^2

first 8 sec : s=ut + 1/2 at^2

= 0 + 5×8^2×1/2

=64×5×1/2

320×1/2

=160 m

Distance covered in next 4 seconds : next part samajh mein nahi aa raha hai

Answer 2

Explanation:

so given,

$initial \: velocity = 0$

$acceleration \: = 5m {s}^{ - 2}$

$time = 8sec$

$v = u + at \\ v = 0 + 5 \times 8 \\ v = 40$

$s = ut + a {t}^{2} \div 2 \\ s = 0(12) + (5) {(12)}^{2} \div 2 \\ s = 5(144) \div 2 \\s = 720 \div 2 \\ s= 360$

hope it will helps you h..... my friend....