Question

1. Cards marked with the numbers 2 to 101 are placed in a box. One card is drawn at random. Find the probability that the card drawn bears a number which is a perfect cube. ​

Answer 1

Step-by-step explanation:

option is

A

1:

2

1

,2:

25

3

,3:

100

9

,4:

25

2

1)Number on cards are 2 to 101

Even number are 2,4,6,..,100=50

Probability that it's an even number =50/100=1/2

2)Numbers less than 14 are 2,3,4,5,6,7,8,9,10,11,12,13=12

Probability=12/100=3/25

3) Perfect square are=4,9,16,25,36,49,64,81,100=9

Probability=9/100

4) Prime number less than 20 are 2,3,5,7,11,13,17,19=8

Probability=8/100=2/25

Answer 2

$\large \boxed{ \textsf{ \textbf{GIVEN \: : - }}} \: \:$

$\:$

• Cards marked with the numbers 2 to 101 are placed in a box.

• One card is drawn at random.

$\:$

$\large \boxed { \textsf{ \textbf{To \: Find \: : - }}}$

$\:$

• Probability that the card drawn bears a number which is a perfect cube ?

$\:$

$\large \boxed{ \textsf{ \textbf{Solution \: : - }}}$

$\:$

$\large \underbrace{ \underline{ \sf{how \: to \: solve \:: :}}}$

$\:$

• We clearly know that, between 2 and 101, there are 3 perfect cubes i.e, 8, 27 and 64. 8 is cube of 2, 27 is cube of 3 and 64 is cube of 4. So, favorable outcomes = 3 and total number of outcomes = 100. So, let's solve it by using well known formula.

$\:$

• $\boxed { \bf{Probability = \frac{Favourable \: outcomes}{total \: numer \: of \: outcomes}}}$

$\:$

$\underline{ \sf{ \bigstar \: Putting \: all \: known \: values \: :: }}$

$\\ \: </p><p></p><p>\begin{gathered}\\ \longrightarrow \:\bf Probability_{(getting\:a\:perfect\:cube)} = \dfrac{3}{100}\end{gathered}$

${ \underline {\sf{more \: information \: on \: brainly :: }}}$

${ \underline{ \red {\sf {QuEsTiOn : }}}}$

$\:$

• Cards marked with the numbers 2 to 101 are placed in a box. One card is drawn at random. Find the probability that the card drawn bears a number which is a perfect cube.

$\:$

${ \underline{ \red{ \sf{AnSwEr \: Given \: by : }}}}$

$\:$

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