1) Charli is counting in steps of5/6
My sequence cannot include
a mixed number containing 1/2
Charli is incorrect.
Prove it by writing a sequence that includes a mixed number containing 1/2
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Answer:
(A) a + 2b = 3ab
(C) a - 2b = 3ab
(B) 1 + 2ab = 3b
(D) 3b + 1 = 2ab(A) a + 2b = 3ab
(C) a - 2b = 3ab
(B) 1 + 2ab = 3b
(D) 3b + 1 = 2ab(A) a + 2b = 3ab
(C) a - 2b = 3ab
(B) 1 + 2ab = 3b
(D) 3b + 1 = 2ab(A) a + 2b = 3ab
(C) a - 2b = 3ab
(B) 1 + 2ab = 3b
(D) 3b + 1 = 2ab(A) a + 2b = 3ab
(C) a - 2b = 3ab
(B) 1 + 2ab = 3b
(D) 3b + 1 = 2ab(A) a + 2b = 3ab
(C) a - 2b = 3ab
(B) 1 + 2ab = 3b
(D) 3b + 1 = 2ab(A) a + 2b = 3ab
(C) a - 2b = 3ab
(B) 1 + 2ab = 3b
(D) 3b + 1 = 2ab(A) a + 2b = 3ab
(C) a - 2b = 3ab
(B) 1 + 2ab = 3b
(D) 3b + 1 = 2ab(A) a + 2b = 3ab
(C) a - 2b = 3ab
(B) 1 + 2ab = 3b
(D) 3b + 1 = 2ab(A) a + 2b = 3ab
(C) a - 2b = 3ab
(B) 1 + 2ab = 3b
(D) 3b + 1 = 2ab(A) a + 2b = 3ab
(C) a - 2b = 3ab
(B) 1 + 2ab = 3b
(D) 3b + 1 = 2ab(A) a + 2b = 3ab
(C) a - 2b = 3ab
(B) 1 + 2ab = 3b
(D) 3b + 1 = 2ab(A) a + 2b = 3ab
(C) a - 2b = 3ab
(B) 1 + 2ab = 3b
(D) 3b + 1 = 2ab(A) a + 2b = 3ab
(C) a - 2b = 3ab
(B) 1 + 2ab = 3b
(D) 3b + 1 = 2ab(A) a + 2b = 3ab
(C) a - 2b = 3ab
(B) 1 + 2ab = 3b
(D) 3b + 1 = 2ab(A) a + 2b = 3ab
(C) a - 2b = 3ab
(B) 1 + 2ab = 3b
(D) 3b + 1 = 2ab(A) a + 2b = 3ab
(C) a - 2b = 3ab
(B) 1 + 2ab = 3b
(D) 3b + 1 = 2ab
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