Question

1. Check 3 and - 2 are the zeroes of the polynomial x² - X-6 or not.
2.Divide and verify the division algorithm of following polynomials:
i) x2 + 5x + 6 by (x + 3)
ii) 3x3 + x2 + 2x + 5 by (1 + 2x​

Answer 1

Answer: 13.3x

Step-by-step explanation: 3 and 2 are zero x$x^{2}$-x  

1 = 2x +5x +6 by (x+3)

2 = 7x + 6 (3x)

3=  7x + 6× 3

4 = 7x + 18

5= x = 7 ÷ 18

6 = so 18 will cut with 2 = 7

7 = 7 ÷ 7

8 = 1

9 = x=1

10 = 1x

2.1 = 3×3 + $x^{2}$ + 2x +5 by (1+2x)

1 = 6 + $x^{2}$+5x (1+2x)

2 = 6$x^{2}$+5x(3x)

3 = 11$x^{2}$×3x

4 = 121 × 3x

5 = x = 121/3

6 = x = 12.3

7 = 12.3x

then = 12.3 + 1

13.3x