Chinese, asked by vishalkrishna771980, 5 months ago

1. Check whether the value given in the
brackets is the root of the given equation
or not.
at 1p + 5 = 19 [p =-2]
b) 4m - 3 = -5 [m=-3]​

Answers

Answered by Samraddhasingh12345
2

Answer:

p = -2 and m= -3 are not roots these equations

Answered by idiot2006
1

LHS RHS

1p + 5 = 19 (1×2) + 5 = 19

1p = 19 - 5 2 + 5 = 19

p = 14 7 ≠ 19

∴ -2 is not the root of the equation 1p + 5 = 19 .

LHS RHS

4m - 3 = -5 (4×-3) -3 = -5

4m = -5 + 3 -12 -3 = -5

4m = -2 -15 ≠ -5

∴ -5 is nit the root of the equation 4m - 3 = -5 .

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