1 Choose the correct option from the following objective questions -
1) I can be subtracted from
a) V b) Vand X c) X and d) V. X and
2) The number of zeros in 100 millions are
a) 7 b) c) d) none of these
3) in a baca is called
a) Minuend b) subtrahend c) difference addend
4) Which of the following operations is performed first in simplifying a
numerical expression ?
a) + b) c) d)
5) How many pairs of parallel lines are there in a rectangle?
b) 2
c) 5
Il Fill in the blanks with suitable answer
7) Angles are measured with the help of a
2) Two parallel lines do not
when they produced
3) The distance between two parallel lines is always
4) perimeter of a circle is called its
line
5)A T-junction of two straight roads is an example of
Answers
Answer:
According to above 100! has trailing zeros.
Answer: B.
For more on this issues check Factorials and Number Theory links in my signature.
Hope it helps.Trailing zeros are a sequence of 0's in the decimal representation (or more generally, in any positional representation) of a number, after which no other digits follow.
Fro example, 125000 has 3 trailing zeros (125000);
The number of trailing zeros in the decimal representation of n!, the factorial of a non-negative integer n, can be determined with this formula:
, where k must be chosen such that 5^(k+1)>n
It's more simple if you look at an example:
How many zeros are in the end (after which no other digits follow) of 32!?
(denominator must be less than 32, is less)
So there are 7 zeros in the end of 32!
The formula actually counts the number of factors 5 in n!, but since there are at least as many factors 2, this is equivalent to the number of factors 10, each of which gives one more trailing zero.the product of all integers from 1 to 100 will have the following number of zeros at the end:
a) 20
b) 24
c) 19
d) 22
e) 28
pls, help with solution method!
Search through the forums (read the math book). There is several threads discussing this.
The number of trailing zeros in 100! is (100/5)+(100/25)=24
Answer : (b)
the question can be re-framed as (100!/10^x) now find x?
100!/(2*5)^x---now factorize 100! by 2 and 5
when factorized by 5 will give the least power 24
Ans 24
Dec 28, 2010
Is this a relevant GMAT question?
Thank you.
Step-by-step explanation:
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