Math, asked by sauravrazz, 10 months ago

1 cm^3 copper is drawn into a wire 0.2 mm in diameter find the length of the wire​

Answers

Answered by nikhil750
16

Answer:

Mark as brainlist

Step-by-step explanation:

Diameter of wire = 0.2 mm = 0.02 cm

Radius of wire = 0.01 cm

Volume of wire = 1 cm^3

=> pi *r^2 * h = 1

=> Length = 1*7/ 22 *0.01*0.01

=> Length = 7 / 22 * 0.0001

=> Length = 70000/22 cm

=> Length of wire = 700/22 m

Length of wire = 31.8 m

Answered by ItzAditt007
1

ANSWER:-

▪︎ Given:-

  • Volume of copper = 1cm³.

  • Diameter of wire = 0.2 mm.

  • Radius of wire = 0.2mm/2 = 0.1 mm

▪︎ To Find:-

  • The length of the wire.

\rule{400}{2}

▪︎ Now,

  • We know that the wire is always in the form of cylinder.

  • So its height would be equal to its length.

  • Let us convert the radius of wire in cm as the volume is in cm³.

\tt\leadsto0.1mm =  \frac{0.1}{10}  \: cm \\  \\\tt (as \: 1cm = 10mm) \\  \\ \tt\large\red{\fbox{\leadsto0.1mm = 0.01 \: cm}}

\rule{400}{2}

▪︎ Also,

• Volume of cylinder = \tt =\pi{r}^{2}h

• Volume of wire = Volume of copper = 1cm³.

\rule{400}{2}

▪︎ Therefore,

\sf \mapsto\pi {r}^{2} h = 1cm {}^{3}  \\  \\ \sf \mapsto  \times  3.14 \times (0.01cm) {}^{2}  \times h = 1cm {}^{3}  \\  \\ \sf \mapsto 3.14\times 0.0001cm {}^{2} \times h = 1cm {}^{3}   \\  \\ \sf \mapsto0.000314  \times h= 1cm {}^{3}  \\  \\ \sf \mapsto \: h =  \frac{1cm {}^{3} }{0.000314 {cm}^{2} }  \\  \\ \sf \mapsto \: h =  \frac{1cm  {}^{3}  }{(314 \times 10 {}^{ - 6})cm {}^{2}  }  \\  \\ \sf \mapsto \: h =  \frac{1000000 \: cm {}^{3} }{314 \: cm {}^{2} } \\  \\  \sf \mapsto \: h = 3184.71\: cm \: (approx) \\  \\  \sf \mapsto \: h = 318.4 \: mm \: (approx) \\  \\ \sf \mapsto\large \pink{\fbox{length = 318.4 \: mm}}

\rule{400}{2}

Therefore the length of the wire is 318.4 mm

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