Question

1 cm of the main scale of a Vernier caliper is divided into 10 equal parts in 10 division of Vernier coincide with 8 small division of men scale then the least count of the vernier calipers

Answer 1

Vernier caliper is an instrument used to measure the internal and external diameters of small tubes.

The least count is the finest measurement you can take with the help of that vernier calipers.

So least count= 1 MSD-1VSD

Here 10 vsd=9 msd

1 vsd=.9 msd

From above LC= 1MSD-1VSD

LC=1MSD-.9MSD=.1MSD(which is equal to .1 mm).

Least count =.1 mm

Answer 2

Answer:

Least count of the vernier calipers is 0.2 mm.

Explanation:

Given 1 cm of main scale of vernier calipers is divided into 10 equal parts

                 i.e., $1MSD=\frac{1cm}{10} =0.1cm=1mm$

and also given, 10 divisions of vernier, coincides with 8 small divisions of main scale  

                i.e., $10VSD=8MSD$

                 $\implies 1VSD=\frac{8}{10} mm$

Least count is the smallest measurement that one can measure using a device.

In vernier calipers, least count is given by

                        $LC= 1 MSD-1VSD$

Substituting the above values,

                         $LC= 1mm-\frac{8}{10}mm$

                               $= \frac{10-8}{10}mm= \frac{2}{10}mm$

                               $=0.2mm$

Least count of the vernier calipers is 0.2 mm.