Question

1) Common difference of an arithmetic sequance is 4 and its 12th term is 66.
(a) Find its 11th term.
(b) Find its first term.​

Answer 1

here is the answer

hope it helps you

Answer 2

Answer:

(a) a12=a11+d

66=a11+4

a11=66-4

a11=62

(b) a12=66

(b) d=4

n=12

an=a+(n-1)d

66=a+(12-1)4

66=a+44

a=66-44

a=22