Math, asked by hasafiya, 4 months ago

1. Complete the following tables by solving sums step wise:
Table1:(Rectangle)

Length Breadth Area Perimeter

i) 2.5 m 1.5 m
ii) 15 m 630 sq. m
iii) 42cm 134cm
iv) 2m 20cm
Table 2( Square)

Side Area Perimeter

i) 6.6 cm
ii) 121 sq m
iii) 20 m
Table3( Circle)

Diameter Radius Circumference Area

i) 14 m
ii) 21 m
iii) 44 cm
iv) 1386 sq cm
Table4(Parallelogram)

Base Height Area

i) 2m 10 cm 20 cm
ii) 1.8 m 2.34 sq m
iii) 10 m 96 sq m
Table4(Triangle)

Base Height Area

i) 9.6 cm 5 cm
ii) 15 m 45 sq m

Answers

Answered by Madankumar808103
0

Answer:

A solution of acetic acid (CH3COOH), methanol (CH3OH), and water is prepared such that the mole fraction of acetic acid is 0.01335, and the mole fraction of methanol is 0.03288. The density of the solution is measured to be 0.9889 g/mL. What is the molarity (in M) of acetic acid in this solutionA solution of acetic acid (CH3COOH), methanol (CH3OH), and water is prepared such that the mole fraction of acetic acid is 0.01335, and the mole fraction of methanol is 0.03288. The density of the solution is measured to be 0.9889 g/mL. What is the molarity (in M) of acetic acid in this solutionA solution of acetic acid (CH3COOH), methanol (CH3OH), and water is prepared such that the mole fraction of acetic acid is 0.01335, and the mole fraction of methanol is 0.03288. The density of the solution is measured to be 0.9889 g/mL. What is the molarity (in M) of acetic acid in this solutionA solution of acetic acid (CH3COOH), methanol (CH3OH), and water is prepared such that the mole fraction of acetic acid is 0.01335, and the mole fraction of methanol is 0.03288. The density of the solution is measured to be 0.9889 g/mL. What is the molarity (in M) of acetic acid in this solutionA solution of acetic acid (CH3COOH), methanol (CH3OH), and water is prepared such that the mole fraction of acetic acid is 0.01335, and the mole fraction of methanol is 0.03288. The density of the solution is measured to be 0.9889 g/mL. What is the molarity (in M) of acetic acid in this solutionA solution of acetic acid (CH3COOH), methanol (CH3OH), and water is prepared such that the mole fraction of acetic acid is 0.01335, and the mole fraction of methanol is 0.03288. The density of the solution is measured to be 0.9889 g/mL. What is the molarity (in M) of acetic acid in this solution

Answered by premshankar991
0

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