Question

1) Complete the table (symbols are not real)

Which element in the table is most stable
One? Justify your answer.
b) Do the element P is stable. Why?
c) How do the elements Q and S attain
stability?​

Answer 1

Answer:

a) R b) No c) Q has to lose two electrons. S has to gain one electron.

Explanation:

a) R is the most stable since its electronic configuration is 2,8. An atom is stable when it has 8 electrons in its valence shell.(in special cases like helium it is 2)

b) P is not stable as it has to gain 1 electron to become stable.

c) Q has to lose 2 electrons. S has to gain 1 electron.

Answer 2

Answer:

$\begin{array}{| c | c | c |}\cline{1-3}\sf Element & \sf Atomic\:number & \sf Electronic\:configuration\\\cline{1-3} P & 9 & 2,7\\\cline{1-3} Q & 17 & 2,8,7\\\cline{1-3} R & 10 & 2,8\\\cline{1-3} S & 12 & 2,8,2\\\cline{1-3}\end{array}$

$\sf{\blue{Here}\begin{cases}\sf P\:is\:flourine\\\sf Q\:is\:Chlorine\\\sf R\:is\:Neon\\\sf S\:is\:Magnesium\end{cases}}$

$\longrightarrow$ Which element in the table is most stable? Justify your answer.

Answer - R ( Neon ) which is a noble gas, is the most stable element, because it's valence shell is complete. (8 Valence electrons are there in it's valence shell).

$\longrightarrow$ Do element P is stable? Why?

Answer - No, element P i.e Flourine isn't stable as it's valence shell isn't complete. It needs to gain one electrone to became stable.

$\longrightarrow$ How do elements Q and S attain stability?

Answer - Element Q i.e chlorine needs to gain one electron to get its valence shell completed and to attain stability.

Element S i.e Magnesium needs to lose two electrons to get its valence shell completed and to attain stability.