Question

1. Compute M.D from median and its relative measure for the following
data
X: 37,49,32,46,56, 40, 42, 53,49​

Answer 1

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Explanation:

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Answer 2

Concept

• The average of the absolute deviations from a central point makes up the average absolute deviation of a data collection.
• It is a statistical summary of statistical variability or dispersion.

Given

Median data 37,49,32,46,56, 40, 42, 53,49 is given

Find

We have to find mean deviation about median

Solution

The steps are as follow:

• First of all we will arrange the given data in increasing order: 32,37,40,42,46,49,49,53,56
• Here n = 9 which is odd
• So the formula to find median will be:

M = (n+1)/2 th observation

M = (9+1)/2 th observation= 10/2 th observation

M = 5th observation

M = 46

• So the formula for finding mean deviation about mean will be as follow:

MD = Sum [X-N]/n

MD =

$\frac{(32 - 46) + (37 - 46) + (40 - 46) + (42 - 46) + (46 - 46) + (49 - 46) + (49 - 46) + (53 - 46) + (56 - 46)}{9}$

• So mean deviation about mean will be -1.11

Hence mean deviation about median for given data of mean will be -1.11

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