Question

1)Compute S.D.and C.V.of marks scored by 10 candidates given<br />below : 54,61,64,69,58,56,49,57,55,50​

Answer 1

Answer: Standard deviation (SD) = 5.79

               Coefficient of Variation (CV) = 0.101

Concept: Mean = (Sum of marks)/Number of students

Standard deviation (SD) = [Sum[(Marks - Mean)^2]/N]^0.5

Coefficient of Variation (CV) = SD/Mean

Given:  Marks 54,61,64,69,58,56,49,57,55,50​

To find: Standard deviation (SD)

               Coefficient of Variation (CV)

Step-by-step explanation:

Marks      

54

61

64

69

58

56

49

57

55

50

Number of students = N

Mean = (Sum of marks)/Number of students

Mean = (54+61+64+69+58+56+49+57+55+50)/10

Mean = 573/10

Mean = 57.3​

(Marks-Mean)^2

10.89

13.69

44.89

136.89

0.49

1.69

68.89

0.09

5.29

53.29

Sum[(Marks - Mean)^2] = 336.1

Standard deviation (SD) = [Sum[(Marks - Mean)^2]/N]^0.5

Standard deviation (SD) = [336.1/10]^0.5

Standard deviation (SD) = 5.79

Coefficient of Variation (CV) = SD/Mean

Coefficient of Variation (CV) =  5.79/57.3

Coefficient of Variation (CV) = 0.101

Answer: Standard deviation (SD) = 5.79

               Coefficient of Variation (CV) = 0.101

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