Question

1.Compute the heat generated while transferring 96000 coulomb of charge in one hour through a potential difference of 50 V.

2. An electric iron of resistance 2012 takes a current of 5 A. Calculate the heat developed in 30 s.​

Answer 1

Answer:

HEY MATE HERE'S YOUR ANSWER

Explanation:

1.

Charge (Q) = 96000 C

Time (t) = 1hr = 60 x 60 = 3600 s

Potential difference (V) = 50 V

Let us calculate current (I)

I = Q/t

I = (96000)/(3600)

I = (80/3) A

Let us calculate the quantity of heat generated by using the formula

H = V × I × t

H = 50 × (80/3) × 3600

H = 4.8 × 106 J

Therefore, the heat generated is 4.8 x 106 J.

2.

Calculate the heat developed in 30 s. H= 100 x 5 x 30 = 1.5 x 104 J. Therefore, the amount of heat developed in the electric iron is 1.5 x 104 J.

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