1 con cost is 3 nupees. 1 goat cost is a rupees.
and 4 chicken cost is 1 rupees. With 20 rupees
how to brought 20 animals
Answers
et number of cows, goats & chicken be x, y & z respectively.
x + y + z = 20
5x + y + z/8 = 20
Solving these simultaneous equations will give the value of x, y & z.
Ideally, you need three equations to solve for three variables.
However, assuming I buy at least Rs 5/- worth cow, Rs 1/- worth goat & Rs 1/- worth chicken, I spend Rs 7/-.
Buying a second set puts me back by Rs 14/-
Rest 6 rupees can be spent in any combination I want :
1 cow + 1 goat ( 5 + 1)
1 cow + 8 chicken (5 + 1)
1 goat + 40 chicken( 1 + 5)
2 goats + 32 chicken ,(2 + 4)
3 goats + 24 chicken (3 + 3)
4 goats + 16 chicken (4 + 2)
5 goats + 8 chicken (5 + 1)
6 goats only (6)
48 chicken only.
Therefore number of animals = 2 Cows, 2 Goats, 16 chicken in round one
PLUS
Any combination listed above
=> Number of animals exceed 20 in every combination.
NO unique solution possible