Question

1. Consider a wave of frequency 500 Hz travelling with a velocity
200 m/s. Find the phase change in a time interval 10-3s. Also find the
path difference between two points that differ by π/2 radian​

Answer 1

Answer:

Explanation:

Answer 2

Concept:

• Wave motion
• Phase changes in waves

Given:

• wave frequency f = 500 Hz
• Wave velocity v = 200 m/s
• Time interval t = 10^-3 s

Find:

• Phase change in the given time interval
• Path difference between two points that differ by π/2 radian​

Solution:

Wavelength of the wave λ = v/f = 200/500 = 0.4 m

In the time t = 10^-3 s, the distance moved by the wave d

d = vt

d = 200*10^-3 = 0.2 m

Here the path difference is 0.2 m

Use the relation,

phase difference in radians =  2πx/λ = 2π* 0.2m/ 0.4m = π

The phase change is π radians and the path difference is 0.2m.

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