Question

1) Consider the curve given by y = f(x) = x^3-x+5.
Find the equation to the line tangent to the curve at the point (1,5).​

Answer 1

Step-by-step explanation:

लयसथसदमसदसणझणबझणणषझढषझषझघफजढषजषजढ

Answer 2

y = f(x) = x³-x+5

$m = \frac{dy}{dx} = {3x}^{2} - 1$

Where m is the slope of the line

Substituting the values in m,

m = 3*1²-1=2

General equation of line:

$(y-y1) = m (x-x1)$

x1=1, y1=5

Substituting the values,

the equation of the line=(y-5)=2(x-1)

Hope it helps you.☺️