Question

1) Consider the equation 2/3 × (p-q) = 1. Which of these can be the values of p and q?
a) p = 3/2, q= 1 ( )
b) p= 5/2 , q= 1
c) p= 3/2 , q= 5/2
d) p= 1, q= 1/2

Answer 1

Given : (2/3) × (p-q) = 1

To Find : Which of these can be the values of p and q?

a) p = 3/2, q= 1  

b) p= 5/2 , q= 1

c) p= 3/2 , q= 5/2

d) p= 1, q= 1/2

Solution:

(2/3) × (p-q) = 1

LHS =   (2/3) × (p-q)

Substitute p = 3/2, q= 1  in LHS

= (2/3) ( 3/2 - 1)

= (2/3) (1/2)

= 1/3

≠ RHS

Substitute p = 5/2, q= 1  in LHS

= (2/3) ( 5/2 - 1)

= (2/3) (3/2)

= 1

= RHS

Hence  p = 5/2, q= 1    can be the values of p and q

Substitute p = 3/2, q= 5/2  in LHS

= (2/3) ( 3/2 - 5/2)

= (2/3) (-1)

= -2/3

≠ RHS

Substitute p = 1, q= 1/2  in LHS

= (2/3) (1 - 1/2)

= (2/3) (1/2)

= 1/3

≠ RHS

Hence correct option is   option  b)  p= 5/2 , q= 1

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Answer 2

Answer:

I will give you the

Step-by-step explanation:

5/2 and q = 1