1) Consider the equation 2/3 × (p-q) = 1. Which of these can be the values of p and q?
a) p = 3/2, q= 1 ( )
b) p= 5/2 , q= 1
c) p= 3/2 , q= 5/2
d) p= 1, q= 1/2
Answers
Given : (2/3) × (p-q) = 1
To Find : Which of these can be the values of p and q?
a) p = 3/2, q= 1
b) p= 5/2 , q= 1
c) p= 3/2 , q= 5/2
d) p= 1, q= 1/2
Solution:
(2/3) × (p-q) = 1
LHS = (2/3) × (p-q)
Substitute p = 3/2, q= 1 in LHS
= (2/3) ( 3/2 - 1)
= (2/3) (1/2)
= 1/3
≠ RHS
Substitute p = 5/2, q= 1 in LHS
= (2/3) ( 5/2 - 1)
= (2/3) (3/2)
= 1
= RHS
Hence p = 5/2, q= 1 can be the values of p and q
Substitute p = 3/2, q= 5/2 in LHS
= (2/3) ( 3/2 - 5/2)
= (2/3) (-1)
= -2/3
≠ RHS
Substitute p = 1, q= 1/2 in LHS
= (2/3) (1 - 1/2)
= (2/3) (1/2)
= 1/3
≠ RHS
Hence correct option is option b) p= 5/2 , q= 1
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Answer:
I will give you the
Step-by-step explanation:
5/2 and q = 1