-1
Consider the equation sin
(32
17
6x +
2
1) -co+* then
then
The largest value of k for which equation has 2 distinct solutions is 1
The equation must have real root if ke
G
2)
The equation must have real root if ke
The equation has unique solution if k
Answers
Answered by
0
Answer:
Step-by-step explanation:
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Answered by
0
Answer:
The root of the given equation x
2
+4x+5=0 are
x=
2
−4±
16−20
=−2±i, where i=
−1
.
Now, for the equation ax
2
+bx+c=0, where a,b,c are positive integers, has a common root with the first equation.
As the two roots of the first equation are complex and a,b,c are natural numbers, the second equation also will have the same roots.
As complex roots occurs in pairs of a quadratic equation with real co-efficient.
For least value of a,b,c we will get least a+b+c
For that case the second equation will be same as the first
So, a+b+c=1+4+5=10.
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