1. Consider the line 4x-3y+12 = 0
a). Find the equation of the line passing through the point (1,2) and parallel to the given line.
b). Find the distance between these two parallel line,
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Answer:
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Answer:
4x-3y=-12
A=4,B=-3
slope=-A/B =-4/-3 =4/3
equation of line with slope 4/3 through (1,2)
y-y1 = m(x-x1)
y-2 = 4/3(x-1)
3(y-2) = 4(x-1)
3y-6 = 4x-4
4x-3y+2=0
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