Question

1 construct a pair of tangents to a
circle of radius 6cm, which are inclined
each other at
an angle of 60 degree​

Answer 1

Answer:

Step-by-step explanation:

We know that radius of the circle is perpendicular to the tangents (∠OPN = ∠ORN = 90°)

Sum of all the 4 angles of quadrilateral = 360°

Angle between the radius (∠POR)  = 360° – (90° + 90° + 60°) = 120°

GIVEN: A circle of radius 5 centimetre and a pair of tangents inclined to each other at an angle of 60°.

STEPS OF CONSTRUCTION:

1.Draw a circle with OS centre and radius 6 centimetre.

2. Draw any diameter POQ of the circle.

3.Draw the radius over means the circle at are such that ∠QOR = 60°.

4.Draw PD ⟂ PQ & RE ⟂ OR.

Let PD &RE  intersect each other at point N. Then NP & NR are the required tangents to the given circle inclined to each other at an angle of 60°.

JUSTIFICATION:

By construction, ∠OPN = 90° and OP is radius  PN is tangent to the circle.

Similarly, NR is a tangent to the circle.

Now, ∠POR = 180° - 60° = 120°

[POQ is a straight line and ∠QOR= 60°]

In quadrilateral OPNR,

∠OPN = 90°, ∠POR = 120° & ∠ORN = 90°.

∠PNR= 360° - ( 90° +120° +90°)

∠PNR = 360° 300° = 60°

HOPE THIS WILL HELP YOU ..