Question

1. Construct a quadrilateral ABCD with sides AB = 3.5 cm, BC= 5 cm, CD = 4.2 cm, A = 110° and B = 80°​

Answer 1

$\huge\pink{\boxed{\red{\textsf {\textbf{An}\blue{\textbf {\textsf{sw}}\pink{\textbf{\textsf{er}}} \orange{\textsf{\textbf{:)}}}}}}}}$

Steps of Construction:

(i) Construct a line segment AB = 3.5 cm.

(ii) Taking A as centre and 4 cm radius construct and arc and with B as centre and 5.4 cm construct an arc which meets the previous arc at the point D.

Now join AD and BD.

(iii) Taking B as centre and 5 cm radius, construct an arc

$\huge\mathfrak\pink\star$Taking D as centre and 5.6 cm radius, construct an arc which meets the previous arc at the point C.

(iv) Join BC and CD.

${: \longrightarrow}$Hence, ABCD is the required quadrilateral.