Math, asked by Anonymous, 4 months ago

(1) Construct a rhombus PQRS, in which PR = 6 cm, PQ = 4 cm.

(2) Construct a rhombus ABCD, in which AB=7 cm, and < A=70°.

(3) Construct a rhombus ZERO, in which ZE=6.2 cm, OE=4.5 cm​


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Answers

Answered by kkmurugan756
3

Step-by-step explanation:

1.PR=6+PQ=4

this construction totally=10

2.----

3.the answer is 38.3is the answer


Anonymous: thanks
Anonymous: but can you tell me steps
Answered by rushikeshphapale4
7

Answer:

We know that, sides of rhombus are equal.

So, PQ=QR=RS=PS=6cm

⇒ Draw a line segment PQ=6cm

⇒ Take P as center with radius 4cm and draw an arc.

⇒ Take Q as center with radius 6cm and draw an arc, which meets previous arc at point R.

⇒ Take P as center with radius 6cm and draw an arc.

⇒ Take R as center with radius 6cm and draw an arc, which meets previous arc at point S.

⇒ Join QR,RS,SP,PR and QS

∴ PQRS is a required rhombus.

⇒ Measure the length of QS.

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